13-tuplet "challenge" in V2

Notessimo
#1

Recently, in my new cover, The Disappearance of Hatsune Miku, I encountered some weird 13:12 and 13:16 tuplets:

I was wondering if any of you know a way to make these perfect? I’m happy with my current solution but I think it could be made better.
You may consider this as a challenge, by the way.

Any ideas?

1 Like
#2

Oh, and the tempo has to be 240. :slight_smile:

#3

It’s probably just supposed to be played with triplets!

#4

This would actually be hell for me.

Literally just… Hell.

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#5

that wouldn’t work. In he treble clef, we can see two whole notes played, while there’s also a quarter rest, implying two different “tracks”, if you will. Along with this, we can see the bass clef perfectly fills out a 4/4 pattern, so we know the bars are in 4/4. Then, if we take 3*4, which is the amount of sixteenth notes available after the quarter rest, it’d be twelve sixteenth notes. So, based off this, velociraptori has to fit 13 evenly spaced notes in an amount of space that could fit 12 sixteenth notes.

In order to do this, the only plausible thing I could imagine is to redo the song, and make 1 sixteenth note = one sixteenth-note 13-tuplet, or something along those lines. Then, have the note length of whole notes be the value of 13 16th notes in the song. However, this would also cause problems, because 13 is prime, and the first few multiples of it aren’t divisible by 16, which is what you’d really need.

Overall, I’d say make it just sixteenth notes and skip one of the notes of the 13 tuplet, as in v2, there’s no real plausible way of doing a 13-tuplet.

#6

You could get the 13:12 to work by setting the tempo 780 and making the note lengths in the tuple dotted eighths, although the rest of it would have to be approximated slightly. I don’t think there is a perfect solution.

#7

Ye that’s exactly the way to do 13-tuplets. Multiplying the speed by 3.25 and the tuplets by 3 for the 13:12 and by 4 for the 13:16 -ones. I used this way in the 4th attempt of my 13-tuplet challenge attempts.
But ye it doesn’t work with triplets at the same time.

#8

Also, if you could get the BPM to 2340 you could make this work exactly by multiplying the note lengths by 39/4. This will simplify the tuplets into 9 sixteenth note lengths for the first 13 tuplet, and 3 quarter note lengths for the second, and 13 sixteenth note lengths for the triplet in the bass of bar 1.